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0=-392-7p^2-105p
We move all terms to the left:
0-(-392-7p^2-105p)=0
We add all the numbers together, and all the variables
-(-392-7p^2-105p)=0
We get rid of parentheses
7p^2+105p+392=0
a = 7; b = 105; c = +392;
Δ = b2-4ac
Δ = 1052-4·7·392
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-7}{2*7}=\frac{-112}{14} =-8 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+7}{2*7}=\frac{-98}{14} =-7 $
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